What is the foci (x^2}{36}-\frac{y^2)/9 =1 ?

The foci (x^2}{36}-\frac{y^2)/9 =1 is (3sqrt(5),0),(-3sqrt(5),0)

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foci (x^2}{36}-\frac{y^2)/9 =1

foci

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

(35, 0), (- 35, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 3^{2} : 35

(0 + 35, 0), (0 - 35, 0)

Refine

(35, 0), (- 35, 0)

y^{2} = x^{2} - 8

\frac{x ^{2}}{36} - \frac{y ^{2}}{13} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 1 ) ^{2}}{9} = 1

\frac{( y - 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{1} = 1

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

What is the foci (x^2}{36}-\frac{y^2)/9 =1 ?
The foci (x^2}{36}-\frac{y^2)/9 =1 is (3sqrt(5),0),(-3sqrt(5),0)