What is the foci ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 ?

The foci ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 is (-6,2+2sqrt(17)),(-6,2-2sqrt(17))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4

foci

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

(- 6, 2 + 217), (- 6, 2 - 217)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4 :

Up-down Hyperbola with

(h, k) = (- 6, 2), a = 214, b = 23

(- 6, 2 + c), (- 6, 2 - c)

Compute

c :

c = (214)^{2} + (23)^{2} : 217

(- 6, 2 + 217), (- 6, 2 - 217)

3 x^{2} - 13 y^{2} - 30 x + 52 y = 16

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

9 x^{2} - 2 y^{2} = 18

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

36 y^{2} - 4 x^{2} = 144

What is the foci ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 ?
The foci ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 is (-6,2+2sqrt(17)),(-6,2-2sqrt(17))