What is the foci 5x^2-2y^2+10x-12y=23 ?

The foci 5x^2-2y^2+10x-12y=23 is (-1+sqrt(7),-3),(-1-sqrt(7),-3)

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foci 5x^2-2y^2+10x-12y=23

foci

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

(- 1 + 7, - 3), (- 1 - 7, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23 :

Right-left Hyperbola with

(h, k) = (- 1, - 3), a = 2, b = 5

(- 1 + c, - 3), (- 1 - c, - 3)

Compute

c :

c = 2^{2} + 5^{2} : 7

(- 1 + 7, - 3), (- 1 - 7, - 3)

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

9 x^{2} = 4 y^{2} - 12

\frac{( x ^{2} )}{4} - 0.2 y^{2} = 1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{49} = 1

\frac{( x + 2 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{5} = 1

What is the foci 5x^2-2y^2+10x-12y=23 ?
The foci 5x^2-2y^2+10x-12y=23 is (-1+sqrt(7),-3),(-1-sqrt(7),-3)