What is the foci (x^2)/2-(y^2)/3 =1 ?

The foci (x^2)/2-(y^2)/3 =1 is (sqrt(5),0),(-sqrt(5),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/2-(y^2)/3 =1

foci

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

(\frac{x - 3}{16})^{2} - \frac{( y - 1 ) ^{2}}{9} = 1

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

x = x^{2} - \frac{y ^{2}}{9}

What is the foci (x^2)/2-(y^2)/3 =1 ?
The foci (x^2)/2-(y^2)/3 =1 is (sqrt(5),0),(-sqrt(5),0)