What is the foci 8x^2-2y^2=16 ?

The foci 8x^2-2y^2=16 is (sqrt(10),0),(-sqrt(10),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 8x^2-2y^2=16

foci

8 x^{2} - 2 y^{2} = 16

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

8 x^{2} - 2 y^{2} = 16 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + (22)^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

4 x^{2} - 12 y^{2} - 16 x - 72 y - 44 = 0

- 25 x^{2} + 36 y^{2} = 900

x^{2} - 9 y^{2} = 36

\frac{( y + 5 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{16} = 1

- x^{2} + \frac{y ^{2}}{20} = 1

What is the foci 8x^2-2y^2=16 ?
The foci 8x^2-2y^2=16 is (sqrt(10),0),(-sqrt(10),0)