What is the foci (y^2)/6-(x^2)/6 =1 ?

The foci (y^2)/6-(x^2)/6 =1 is (0,2sqrt(3)),(0,-2sqrt(3))

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foci (y^2)/6-(x^2)/6 =1

foci

\frac{y ^{2}}{6} - \frac{x ^{2}}{6} = 1

(0, 23), (0, - 23)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{6} - \frac{x ^{2}}{6} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 6^{2} : 23

(0, 0 + 23), (0, 0 - 23)

Refine

(0, 23), (0, - 23)

x^{2} - y^{2} - 2 x - 6 y - 12 = 0

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

4 x^{2} - 9 y^{2} = 144

\frac{( y - \frac{9}{2} ) ^{2}}{49} - \frac{( x - \frac{7}{2} ) ^{2}}{49} = 1

9 x^{2} - 4 y^{2} + 18 x - 27 = 0

What is the foci (y^2)/6-(x^2)/6 =1 ?
The foci (y^2)/6-(x^2)/6 =1 is (0,2sqrt(3)),(0,-2sqrt(3))