What is the foci-4x^2+y^2=36 ?

The foci-4x^2+y^2=36 is (0,3sqrt(5)),(0,-3sqrt(5))

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foci-4x^2+y^2=36

foci

- 4 x^{2} + y^{2} = 36

(0, 35), (0, - 35)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- 4 x^{2} + y^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 3^{2} : 35

(0, 0 + 35), (0, 0 - 35)

Refine

(0, 35), (0, - 35)

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

x^{2} - y^{2} = 100

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

\frac{( x + 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{4} = 1

x^{2} - y^{2} - 10 x - 10 y - 1 = 0

What is the foci-4x^2+y^2=36 ?
The foci-4x^2+y^2=36 is (0,3sqrt(5)),(0,-3sqrt(5))