What is the foci 9y^2-4x^2=36 ?

The foci 9y^2-4x^2=36 is (0,sqrt(13)),(0,-sqrt(13))

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foci 9y^2-4x^2=36

foci

9 y^{2} - 4 x^{2} = 36

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

9 y^{2} - 4 x^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 3^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

\frac{( y - 1 ) ^{2}}{9} - \frac{( x + 3 ) ^{2}}{16} = 1

81 x^{2} + 972 x - 16 y^{2} - 128 y + 1364 = 0

36 x^{2} - 4 y^{2} = 144

(\frac{y}{49})^{2} - (\frac{x}{36})^{2} = 1

25 y^{2} - 64 x^{2} = 1600

What is the foci 9y^2-4x^2=36 ?
The foci 9y^2-4x^2=36 is (0,sqrt(13)),(0,-sqrt(13))