What is the foci (x^2}{18}-\frac{y^2)/7 =1 ?

The foci (x^2}{18}-\frac{y^2)/7 =1 is (5,0),(-5,0)

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foci (x^2}{18}-\frac{y^2)/7 =1

foci

\frac{x ^{2}}{18} - \frac{y ^{2}}{7} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{18} - \frac{y ^{2}}{7} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 32, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (32)^{2} + 7^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

\frac{( x ^{2} )}{4} - 0.14 y^{2} = 1

\frac{x ^{2}}{( \frac{64}{7} )} - \frac{y ^{2}}{( \frac{48}{7} )} = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 4 ) ^{2}}{144} = 1

y^{2} - x^{2} = 36

What is the foci (x^2}{18}-\frac{y^2)/7 =1 ?
The foci (x^2}{18}-\frac{y^2)/7 =1 is (5,0),(-5,0)