What is the foci (x^2)/4-(y^2)/(49)=1 ?

The foci (x^2)/4-(y^2)/(49)=1 is (sqrt(53),0),(-sqrt(53),0)

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foci (x^2)/4-(y^2)/(49)=1

foci

\frac{x ^{2}}{4} - \frac{y ^{2}}{49} = 1

(53, 0), (- 53, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 7

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 7^{2} : 53

(0 + 53, 0), (0 - 53, 0)

Refine

(53, 0), (- 53, 0)

\frac{( y - 1 ) ^{2}}{4} - \frac{( x + 8 ) ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{11} - \frac{( y + 1 ) ^{2}}{5} = 1

16 x^{2} - y^{2} - 96 x - 6 y + 119 = 0

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

18 x^{2} - 32 y^{2} = 2

What is the foci (x^2)/4-(y^2)/(49)=1 ?
The foci (x^2)/4-(y^2)/(49)=1 is (sqrt(53),0),(-sqrt(53),0)