What is the foci ((y^2)}{27}-\frac{(x^2))/9 =1 ?

The foci ((y^2)}{27}-\frac{(x^2))/9 =1 is (0,6),(0,-6)

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foci ((y^2)}{27}-\frac{(x^2))/9 =1

foci

\frac{( y ^{2} )}{27} - \frac{( x ^{2} )}{9} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{27} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 33, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (33)^{2} + 3^{2} : 6

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

64 x^{2} - 100 y^{2} = 6400

(\frac{( x ^{2} )}{27}) - \frac{( ( y - 3 ) ^{2} )}{36} = 1

\frac{( x - 7 ) ^{2}}{25} - \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{5} - \frac{y ^{2}}{7} = 1

\frac{( x - 6 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{9} = 1

What is the foci ((y^2)}{27}-\frac{(x^2))/9 =1 ?
The foci ((y^2)}{27}-\frac{(x^2))/9 =1 is (0,6),(0,-6)