What is the foci (y^2)/9-(x^2)/1 =1 ?

The foci (y^2)/9-(x^2)/1 =1 is (0,sqrt(10)),(0,-sqrt(10))

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foci (y^2)/9-(x^2)/1 =1

foci

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} + 1^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{25} = 1

4 x^{2} - 8 y^{2} = 3

\frac{y ^{2}}{1600} - \frac{x ^{2}}{5625} = 1

\frac{( x + 2 ) ^{2}}{64} - \frac{( y - 3 ) ^{2}}{36} = 1

\frac{( y + 2 ) ^{2}}{25} - \frac{( x + 4 ) ^{2}}{9} = 1

What is the foci (y^2)/9-(x^2)/1 =1 ?
The foci (y^2)/9-(x^2)/1 =1 is (0,sqrt(10)),(0,-sqrt(10))