What is the foci x^2-y^2=4x ?

The foci x^2-y^2=4x is (2+2sqrt(2),0),(2-2sqrt(2),0)

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foci x^2-y^2=4x

foci

x^{2} - y^{2} = 4 x

(2 + 22, 0), (2 - 22, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 4 x :

Right-left Hyperbola with

(h, k) = (2, 0), a = 2, b = 2

(2 + c, 0), (2 - c, 0)

Compute

c :

c = 2^{2} + 2^{2} : 22

(2 + 22, 0), (2 - 22, 0)

y^{2} - x^{2} = 1

(y + 4)^{2} - \frac{( x - 2 ) ^{2}}{4} = 1

\frac{( x - 6 ) ^{2}}{8} - \frac{( y - 5 ) ^{2}}{1} = 1

\frac{x ^{2}}{16} - \frac{( y + 5 ) ^{2}}{9} = 1

4 x^{2} = y^{2} + 4

What is the foci x^2-y^2=4x ?
The foci x^2-y^2=4x is (2+2sqrt(2),0),(2-2sqrt(2),0)