What is the foci (x^2)/(45)-(y^2)/(360)=1 ?

The foci (x^2)/(45)-(y^2)/(360)=1 is (9sqrt(5),0),(-9sqrt(5),0)

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foci (x^2)/(45)-(y^2)/(360)=1

foci

\frac{x ^{2}}{45} - \frac{y ^{2}}{360} = 1

(95, 0), (- 95, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{45} - \frac{y ^{2}}{360} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 35, b = 610

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (35)^{2} + (610)^{2} : 95

(0 + 95, 0), (0 - 95, 0)

Refine

(95, 0), (- 95, 0)

\frac{y ^{2}}{225} - \frac{x ^{2}}{64} = 1

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

x^{2} - y^{2} = 13

What is the foci (x^2)/(45)-(y^2)/(360)=1 ?
The foci (x^2)/(45)-(y^2)/(360)=1 is (9sqrt(5),0),(-9sqrt(5),0)