What is the foci (y^2)/(25)-(x^2)/(36)=1 ?

The foci (y^2)/(25)-(x^2)/(36)=1 is (0,sqrt(61)),(0,-sqrt(61))

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foci (y^2)/(25)-(x^2)/(36)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{36} = 1

(0, 61), (0, - 61)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 6^{2} : 61

(0, 0 + 61), (0, 0 - 61)

Refine

(0, 61), (0, - 61)

\frac{( x - 1 ) ^{2}}{12} - \frac{( y - 2 ) ^{2}}{8} = 1

- x^{2} + 25 \cdot y^{2} = 25

4 x^{2} - y^{2} + 12 x + 5 = 0

\frac{( x - 13 ) ^{2}}{144} - \frac{y ^{2}}{25} = 1

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

What is the foci (y^2)/(25)-(x^2)/(36)=1 ?
The foci (y^2)/(25)-(x^2)/(36)=1 is (0,sqrt(61)),(0,-sqrt(61))