What is the foci 5y^2-16x^2+400=0 ?

The foci 5y^2-16x^2+400=0 is (sqrt(105),0),(-sqrt(105),0)

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foci 5y^2-16x^2+400=0

foci

5 y^{2} - 16 x^{2} + 400 = 0

(105, 0), (- 105, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

5 y^{2} - 16 x^{2} + 400 = 0 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 45

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + (45)^{2} : 105

(0 + 105, 0), (0 - 105, 0)

Refine

(105, 0), (- 105, 0)

\frac{x ^{2}}{36} - \frac{( y - 10 ) ^{2}}{64} = 1

\frac{( y - 1 ) ^{2}}{49} - \frac{( x - 2 ) ^{2}}{32} = 1

\frac{( x - 3 ) ^{2}}{13} - \frac{( y - 5 ) ^{2}}{7} = 1

\frac{y ^{2}}{10} - \frac{( x - 1 ) ^{2}}{10} = 1

- 4 x^{2} + y^{2} + 6 y - 27 = 0

What is the foci 5y^2-16x^2+400=0 ?
The foci 5y^2-16x^2+400=0 is (sqrt(105),0),(-sqrt(105),0)