What is the foci (x^2)/1-(y^2)/(35)=1 ?

The foci (x^2)/1-(y^2)/(35)=1 is (6,0),(-6,0)

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foci (x^2)/1-(y^2)/(35)=1

foci

\frac{x ^{2}}{1} - \frac{y ^{2}}{35} = 1

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{1} - \frac{y ^{2}}{35} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 35

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1^{2} + 35^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

x^{2} - 36 y^{2} = 36

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

\frac{( y - 1 ) ^{2}}{\frac{1}{4}} - \frac{( x + 1 ) ^{2}}{\frac{1}{16}} = 1

64 y^{2} - 4 x^{2} = 256

4 x^{2} - y^{2} - 24 x + 20 = 0

What is the foci (x^2)/1-(y^2)/(35)=1 ?
The foci (x^2)/1-(y^2)/(35)=1 is (6,0),(-6,0)