What is the foci ((y+2)^2)/9-((x-1)^2)/(64)=1 ?

The foci ((y+2)^2)/9-((x-1)^2)/(64)=1 is (1,-2+sqrt(73)),(1,-2-sqrt(73))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((y+2)^2)/9-((x-1)^2)/(64)=1

foci

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{64} = 1

(1, - 2 + 73), (1, - 2 - 73)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (1, - 2), a = 3, b = 8

(1, - 2 + c), (1, - 2 - c)

Compute

c :

c = 3^{2} + 8^{2} : 73

(1, - 2 + 73), (1, - 2 - 73)

\frac{x ^{2}}{37} - \frac{y ^{2}}{63} = 1

3 x^{2} - y^{2} = 300

4 x^{2} - y^{2} = 4

(x - 1)^{2} - (y - 2)^{2} = 3

4 x^{2} - y^{2} - 6 y - 25 = 0

What is the foci ((y+2)^2)/9-((x-1)^2)/(64)=1 ?
The foci ((y+2)^2)/9-((x-1)^2)/(64)=1 is (1,-2+sqrt(73)),(1,-2-sqrt(73))