What is y^2-6x+5y-13=0 ?

The solution to y^2-6x+5y-13=0 is Parabola with (h,k)=(-77/24 ,-5/2),p= 3/2

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y^2-6x+5y-13=0

y^{2} - 6 x + 5 y - 13 = 0

(h, k) = (- \frac{77}{24}, - \frac{5}{2}), p = \frac{3}{2}

Solution steps

y^{2} - 6 x + 5 y - 13 = 0

Rewrite

y^{2} - 6 x + 5 y - 13 = 0

in the standard form

4 \cdot \frac{3}{2} (x - (- \frac{77}{24})) = (y - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{77}{24}, - \frac{5}{2}), p = \frac{3}{2}

x^{2} + 2 x - 16 y + 65 = 0

(x + 3)^{2} = - 4 (y + 3)

x^{2} - 4 x + 20 y - 56 = 0

- f (x) = 3 x^{2} + 4 x - 4

y - 3 = x^{2}

What is y^2-6x+5y-13=0 ?
The solution to y^2-6x+5y-13=0 is Parabola with (h,k)=(-77/24 ,-5/2),p= 3/2