What is the foci (x^2)/(49)-(y^2)/(81)=1 ?

The foci (x^2)/(49)-(y^2)/(81)=1 is (sqrt(130),0),(-sqrt(130),0)

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foci (x^2)/(49)-(y^2)/(81)=1

foci

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

(130, 0), (- 130, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 9

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 9^{2} : 130

(0 + 130, 0), (0 - 130, 0)

Refine

(130, 0), (- 130, 0)

\frac{y ^{2}}{6} - \frac{x ^{2}}{11} = 1

4 x^{2} - y^{2} - 32 x + 60 = 0

\frac{x ^{2}}{625} - \frac{y ^{2}}{3600} = 1

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{64} = 1

What is the foci (x^2)/(49)-(y^2)/(81)=1 ?
The foci (x^2)/(49)-(y^2)/(81)=1 is (sqrt(130),0),(-sqrt(130),0)