What is the foci 2y^2-(x^2)/2 =2 ?

The foci 2y^2-(x^2)/2 =2 is (0,sqrt(5)),(0,-sqrt(5))

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foci 2y^2-(x^2)/2 =2

foci

2 y^{2} - \frac{x ^{2}}{2} = 2

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

2 y^{2} - \frac{x ^{2}}{2} = 2 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{y ^{2}}{25} - \frac{( x + 3 ) ^{2}}{56} = 1

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 3 ) ^{2}}{4} = 1

25 x^{2} - 9 y^{2} = 225

\frac{( y - 5 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{4} - (y + 3)^{2} = 1

What is the foci 2y^2-(x^2)/2 =2 ?
The foci 2y^2-(x^2)/2 =2 is (0,sqrt(5)),(0,-sqrt(5))