What is the foci x^2-y^2-6x+16y-119=0 ?

The foci x^2-y^2-6x+16y-119=0 is (3+8sqrt(2),8),(3-8sqrt(2),8)

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foci x^2-y^2-6x+16y-119=0

foci

x^{2} - y^{2} - 6 x + 16 y - 119 = 0

(3 + 82, 8), (3 - 82, 8)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} - 6 x + 16 y - 119 = 0 :

Right-left Hyperbola with

(h, k) = (3, 8), a = 8, b = 8

(3 + c, 8), (3 - c, 8)

Compute

c :

c = 8^{2} + 8^{2} : 82

(3 + 82, 8), (3 - 82, 8)

9 x^{2} - 25 y^{2} = 900

(\frac{x - 5}{8})^{2} - (\frac{y + 2}{7})^{2} = 1

3 x^{2} - y^{2} = 3

(\frac{x ^{2}}{16}) - (\frac{y ^{2}}{9}) = 1

\frac{x ^{2}}{34} - \frac{y ^{2}}{2} = 1

What is the foci x^2-y^2-6x+16y-119=0 ?
The foci x^2-y^2-6x+16y-119=0 is (3+8sqrt(2),8),(3-8sqrt(2),8)