What is the asymptotes of (x^2)/(16)-(y^2)/(64)=1 ?

The asymptotes of (x^2)/(16)-(y^2)/(64)=1 is y=2x,\quad y=-2x

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asymptotes of (x^2)/(16)-(y^2)/(64)=1

asymptotes

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

y = 2 x, y = - 2 x

Solution steps

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 8

y = \frac{8}{4} (x - 0) + 0, y = - \frac{8}{4} (x - 0) + 0

Refine

y = 2 x, y = - 2 x

\frac{y ^{2}}{49} - \frac{x ^{2}}{36} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

\frac{( y - 5 ) ^{2}}{16} - (x + 5)^{2} = 1

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

- 1 = x^{2} - y^{2}

What is the asymptotes of (x^2)/(16)-(y^2)/(64)=1 ?
The asymptotes of (x^2)/(16)-(y^2)/(64)=1 is y=2x,\quad y=-2x