asymptoten-(x^2}{16}+\frac{y^2)/9 =1

Lösung

asymptoten

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

Schritte zur Lösung

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 4

y = \frac{3}{4} (x - 0) + 0, y = - \frac{3}{4} (x - 0) + 0

Fasse zusammen

y = \frac{3 x}{4}, y = - \frac{3 x}{4}

a sy m pt o t es 4 x^{2} - y^{2} + 16 x + 6 y = 9

a sy m pt o t es 9 x^{2} - 25 y^{2} - 72 x + 369 = 0

a sy m pt o t es 6 x^{2} - \frac{2}{3} y^{2} = 4

a sy m pt o t es 4 (x - 3)^{2} - 9 (y - 2)^{2} = 36

a sy m pt o t es \frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1