What is 4y^2+3x-6y-12=0 ?

The solution to 4y^2+3x-6y-12=0 is Parabola with (h,k)=(19/4 , 3/4),p=-3/16

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4y^2+3x-6y-12=0

4 y^{2} + 3 x - 6 y - 12 = 0

(h, k) = (\frac{19}{4}, \frac{3}{4}), p = - \frac{3}{16}

Solution steps

4 y^{2} + 3 x - 6 y - 12 = 0

Rewrite

4 y^{2} + 3 x - 6 y - 12 = 0

in the standard form

4 (- \frac{3}{16}) (x - \frac{19}{4}) = (y - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{19}{4}, \frac{3}{4}), p = - \frac{3}{16}

y = - \frac{x}{y}

25 (x + 2)^{2} + y = (x - 7)^{2} - 81

- 2 x^{2} + 6 x - 2 y - 1 = 0

x = - 4 y^{2}

x^{2} = 24 (y - 8)

What is 4y^2+3x-6y-12=0 ?
The solution to 4y^2+3x-6y-12=0 is Parabola with (h,k)=(19/4 , 3/4),p=-3/16