What is the center ((y+4)^2)/9-((x+2)^2)/4 =1 ?

The center ((y+4)^2)/9-((x+2)^2)/4 =1 is (-2,-4)

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center ((y+4)^2)/9-((x+2)^2)/4 =1

center

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

(- 2, - 4)

Solution steps

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 4), a = 3, b = 2

And the center is:

(- 2, - 4)

2 y^{2} - x^{2} - y + x = 0

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

\frac{( y - 7 ) ^{2}}{9} - (x + 4)^{2} = 1

2 y^{2} - 9 x^{2} - 18 x + 20 + 5 = 0

What is the center ((y+4)^2)/9-((x+2)^2)/4 =1 ?
The center ((y+4)^2)/9-((x+2)^2)/4 =1 is (-2,-4)