What is the eccentricity 16x^2-96x-y^2-2y+139=0 ?

The eccentricity 16x^2-96x-y^2-2y+139=0 is square root of 17

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eccentricity 16x^2-96x-y^2-2y+139=0

eccentricity

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0

17

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

16 x^{2} - 96 x - y^{2} - 2 y + 139 = 0 :

Right-left Hyperbola with

(h, k) = (3, - 1), a = \frac{1}{2}, b = 2

= \frac{( \frac{1}{2} ) ^{2} + 2 ^{2}}{\frac{1}{2}}

Refine

= 17

9 x^{2} - 4 y^{2} = 36

y^{2} - 4 x^{2} + 4 x - 2 y - 4 = 0

16 x^{2} - 4 y^{2} = 49

16 x^{2} - 25 y^{2} = 64

25 x^{2} - 9 y^{2} = 225

What is the eccentricity 16x^2-96x-y^2-2y+139=0 ?
The eccentricity 16x^2-96x-y^2-2y+139=0 is square root of 17