What is the eccentricity (x^2)/(121)-(y^2)/(81)=1 ?

The eccentricity (x^2)/(121)-(y^2)/(81)=1 is (sqrt(202))/(11)

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eccentricity (x^2)/(121)-(y^2)/(81)=1

eccentricity

\frac{x ^{2}}{121} - \frac{y ^{2}}{81} = 1

\frac{202}{11}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{121} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 11, b = 9

= \frac{1 1 ^{2} + 9 ^{2}}{11}

Refine

= \frac{202}{11}

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

x^{2} - \frac{y ^{2}}{4} = 1

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

What is the eccentricity (x^2)/(121)-(y^2)/(81)=1 ?
The eccentricity (x^2)/(121)-(y^2)/(81)=1 is (sqrt(202))/(11)