What is the eccentricity (y^2)/4-(x^2)/5 =1 ?

The eccentricity (y^2)/4-(x^2)/5 =1 is 3/2

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eccentricity (y^2)/4-(x^2)/5 =1

eccentricity

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

\frac{3}{2}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 5

= \frac{2 ^{2} + ( 5 ) ^{2}}{2}

Refine

= \frac{3}{2}

9 x^{2} - 9 y^{2} + 18 x + 36 y = 63

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

\frac{( x - 2 ) ^{2}}{9} - (y + 1)^{2} = 1

+ x^{2} - y^{2} = 4

y^{2} - 4 y - 4 x^{2} + 13 = 0

What is the eccentricity (y^2)/4-(x^2)/5 =1 ?
The eccentricity (y^2)/4-(x^2)/5 =1 is 3/2