What is the vertexform h(x)=x^2-14x+6 ?

The vertexform h(x)=x^2-14x+6 is Minimum (7,-43)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

Find the Vertex Form h(x)=x^2-14x+6

vertex form

h (x) = x^{2} - 14 x + 6

Minimum (7, - 43)

Solution steps

y = x^{2} - 14 x + 6

Rewrite

y = x^{2} - 14 x + 6

in the vertex form

y = (x - 7)^{2} - 43

The parabola parameters are:

a = 1, h = 7, k = - 43

Therefore the parabola vertex is

(h, k) = (7, - 43)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (7, - 43)

y = - 6 x^{2} + 3 x + 2

8 x^{2} - 48 x + 65

x^{2} + y^{2} - 8 x - 6 y + 21 = 0

f (x) = x^{2} - 14 x + 6

f (x) = x^{2} - 6 x - 4

What is the vertexform h(x)=x^2-14x+6 ?
The vertexform h(x)=x^2-14x+6 is Minimum (7,-43)