What is the vertexform h(x)=x^2-14x+6 ?

The vertexform h(x)=x^2-14x+6 is Minimum (7,-43)

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Find the Vertex Form h(x)=x^2-14x+6

vertexform

Minimum (7, - 43)

Solution steps

y = x^{2} - 14 x + 6

Rewrite

y = x^{2} - 14 x + 6

in the vertex form

y = (x - 7)^{2} - 43

The parabola parameters are:

a = 1, h = 7, k = - 43

Therefore the parabola vertex is

(h, k) = (7, - 43)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (7, - 43)

What is the vertexform h(x)=x^2-14x+6 ?
The vertexform h(x)=x^2-14x+6 is Minimum (7,-43)