What is f(x)=x^2-2x+5.4f(x) ?

The solution to f(x)=x^2-2x+5.4f(x) is Parabola with (h,k)=(1,0.22727…),p=-1.1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=x^2-2x+5.4f(x)

f (x) = x^{2} - 2 x + 5.4 f (x)

(h, k) = (1, 0.22727 \dots), p = - 1.1

Solution steps

y = x^{2} - 2 x + 5.4 y

Rewrite

y = x^{2} - 2 x + 5.4 y

in the standard form

4 (- 1.1) (y - 0.22727 \dots) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 0.22727 \dots), p = - 1.1

x^{2} - 10 x - 12 y - 23 = 0

(y - 1)^{2} = 16 x

(y + 1)^{2} = - 16 (x - 5)

9 x^{2} = 16 y

(x + 3)^{2} = - 12 (y + 3)

What is f(x)=x^2-2x+5.4f(x) ?
The solution to f(x)=x^2-2x+5.4f(x) is Parabola with (h,k)=(1,0.22727…),p=-1.1