What is 3y^2-2(4+5x)=2y^2+x ?

The solution to 3y^2-2(4+5x)=2y^2+x is Parabola with (h,k)=(-8/11 ,0),p= 11/4

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3y^2-2(4+5x)=2y^2+x

3 y^{2} - 2 (4 + 5 x) = 2 y^{2} + x

(h, k) = (- \frac{8}{11}, 0), p = \frac{11}{4}

Solution steps

3 y^{2} - 2 (4 + 5 x) = 2 y^{2} + x

Rewrite

3 y^{2} - 2 (4 + 5 x) = 2 y^{2} + x

in the standard form:

4 \cdot \frac{11}{4} (x - (- \frac{8}{11})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{8}{11}, 0), p = \frac{11}{4}

(x - 1)^{2} = - 8 (y + 2)

x = (y + 6)^{2}

- f (x) = 2 x^{2} + x - 1

x^{2} + 5 x - \frac{1}{4} y + 6 = 0

1 - x^{2} - y = 0

What is 3y^2-2(4+5x)=2y^2+x ?
The solution to 3y^2-2(4+5x)=2y^2+x is Parabola with (h,k)=(-8/11 ,0),p= 11/4