What is (3x^2)-12x-8y-4=0 ?

The solution to (3x^2)-12x-8y-4=0 is Parabola with (h,k)=(2,-2),p= 2/3

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(3x^2)-12x-8y-4=0

(3 x^{2}) - 12 x - 8 y - 4 = 0

(h, k) = (2, - 2), p = \frac{2}{3}

Solution steps

3 x^{2} - 12 x - 8 y - 4 = 0

Rewrite

3 x^{2} - 12 x - 8 y - 4 = 0

in the standard form

4 \cdot \frac{2}{3} (y - (- 2)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 2), p = \frac{2}{3}

4 x^{2} - 3 y = 0

2 x^{2} - 8 + b y (x) + 10 = 0

2 x - 3 y^{2} = 18

- 4 x + y^{2} - 8 = 0

(x - 4)^{2} = - 12 (y - 3)

What is (3x^2)-12x-8y-4=0 ?
The solution to (3x^2)-12x-8y-4=0 is Parabola with (h,k)=(2,-2),p= 2/3