What is (x+2/5)^2+(y+2/3)=10 ?

The solution to (x+2/5)^2+(y+2/3)=10 is Parabola with (h,k)=(-2/5 , 28/3),p=-1/4

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(x+2/5)^2+(y+2/3)=10

(x + \frac{2}{5})^{2} + (y + \frac{2}{3}) = 10

(h, k) = (- \frac{2}{5}, \frac{28}{3}), p = - \frac{1}{4}

Solution steps

(x + \frac{2}{5})^{2} + (y + \frac{2}{3}) = 10

Rewrite

(x + \frac{2}{5})^{2} + (y + \frac{2}{3}) = 10

in the standard form:

4 (- \frac{1}{4}) (y - \frac{28}{3}) = (x - (- \frac{2}{5}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{5}, \frac{28}{3}), p = - \frac{1}{4}

3 y^{2} + 4 x - 24 y + 44 = 0

4 x^{2} + 2 y = 10

(y + 7)^{2} = 4 (x - 1)

x^{2} - y > 0

(y - 2)^{2} = 40 (x - 2)

What is (x+2/5)^2+(y+2/3)=10 ?
The solution to (x+2/5)^2+(y+2/3)=10 is Parabola with (h,k)=(-2/5 , 28/3),p=-1/4