What is (x-2)+(y-1)^{(2)}-25=0 ?

The solution to (x-2)+(y-1)^{(2)}-25=0 is Parabola with (h,k)=(27,1),p=-1/4

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(x-2)+(y-1)^{(2)}-25=0

(x - 2) + (y - 1)^{(2)} - 25 = 0

(h, k) = (27, 1), p = - \frac{1}{4}

Solution steps

x - 2 + (y - 1)^{2} - 25 = 0

Rewrite

x - 2 + (y - 1)^{2} - 25 = 0

in the standard form:

4 (- \frac{1}{4}) (x - 27) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (27, 1), p = - \frac{1}{4}

x 3 x + 2 y = 10

x = - \frac{1}{7} y^{2} + 4

(y - 3)^{2} = 8 (x + 2)

(x - 3)^{2} = - 8 (y + 1)

y > - 2 (x + 1) (x - 7)

What is (x-2)+(y-1)^{(2)}-25=0 ?
The solution to (x-2)+(y-1)^{(2)}-25=0 is Parabola with (h,k)=(27,1),p=-1/4