What is 4x^2-12x-24y-16=0 ?

The solution to 4x^2-12x-24y-16=0 is Parabola with (h,k)=(3/2 ,-25/24),p= 3/2

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4x^2-12x-24y-16=0

4 x^{2} - 12 x - 24 y - 16 = 0

(h, k) = (\frac{3}{2}, - \frac{25}{24}), p = \frac{3}{2}

Solution steps

4 x^{2} - 12 x - 24 y - 16 = 0

Rewrite

4 x^{2} - 12 x - 24 y - 16 = 0

in the standard form

4 \cdot \frac{3}{2} (y - (- \frac{25}{24})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{25}{24}), p = \frac{3}{2}

x = (y + 1)^{2}

x^{2} + (y - 5) 2 = 9

x^{2} - 4 y + 4 = 0

1 6^{2} + 25 y^{2} + 32 x - 150 y - 159 = 0

x = - y^{(2)} + 8 y - 14

What is 4x^2-12x-24y-16=0 ?
The solution to 4x^2-12x-24y-16=0 is Parabola with (h,k)=(3/2 ,-25/24),p= 3/2