What is 3f(2x)=2x^2-3x+1 ?

The solution to 3f(2x)=2x^2-3x+1 is Parabola with (h,k)=(3/4 ,-1/24),p= 3/8

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3f(2x)=2x^2-3x+1

3 f (2 x) = 2 x^{2} - 3 x + 1

(h, k) = (\frac{3}{4}, - \frac{1}{24}), p = \frac{3}{8}

Solution steps

3 y = 2 x^{2} - 3 x + 1

Rewrite

3 y = 2 x^{2} - 3 x + 1

in the standard form

4 \cdot \frac{3}{8} (y - (- \frac{1}{24})) = (x - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{4}, - \frac{1}{24}), p = \frac{3}{8}

5 x^{2} + 100 y = 0

- 6 x + x^{2} + 12 y - 15 = 0

x^{2} + y + 2 x - 4 y - 4 = 0

x^{2} + (y + 1) 2 = 36

(- y)^{2} = x + 16

What is 3f(2x)=2x^2-3x+1 ?
The solution to 3f(2x)=2x^2-3x+1 is Parabola with (h,k)=(3/4 ,-1/24),p= 3/8