What is 3x^2-5x+2y+1=0 ?

The solution to 3x^2-5x+2y+1=0 is Parabola with (h,k)=(5/6 , 13/24),p=-1/6

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3x^2-5x+2y+1=0

3 x^{2} - 5 x + 2 y + 1 = 0

(h, k) = (\frac{5}{6}, \frac{13}{24}), p = - \frac{1}{6}

Solution steps

3 x^{2} - 5 x + 2 y + 1 = 0

Rewrite

3 x^{2} - 5 x + 2 y + 1 = 0

in the standard form

4 (- \frac{1}{6}) (y - \frac{13}{24}) = (x - \frac{5}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{6}, \frac{13}{24}), p = - \frac{1}{6}

y^{2} - 12 x + 20 = 0

y^{2} + 6 y - 12 x - 15 = 0

y 6 y = 24 - 3 x

x 2 x - 3 y = 2

y = x^{2} - y

What is 3x^2-5x+2y+1=0 ?
The solution to 3x^2-5x+2y+1=0 is Parabola with (h,k)=(5/6 , 13/24),p=-1/6