What is 2y^2-16x+16(y-1)+16=-2y^2 ?

The solution to 2y^2-16x+16(y-1)+16=-2y^2 is Parabola with (h,k)=(-1,-2),p=1

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2y^2-16x+16(y-1)+16=-2y^2

2 y^{2} - 16 x + 16 (y - 1) + 16 = - 2 y^{2}

(h, k) = (- 1, - 2), p = 1

Solution steps

2 y^{2} - 16 x + 16 (y - 1) + 16 = - 2 y^{2}

Rewrite

2 y^{2} - 16 x + 16 (y - 1) + 16 = - 2 y^{2}

in the standard form

4 \cdot 1 \cdot (x - (- 1)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 2), p = 1

(x - 2)^{2} + (y - 1) = 9

x + y^{2} = c

- 6 x^{2} + y + 1 = 0

x^{2} - 32 x - 3 m (x) - 8 = 0

y 3 y - 2 x = 12

What is 2y^2-16x+16(y-1)+16=-2y^2 ?
The solution to 2y^2-16x+16(y-1)+16=-2y^2 is Parabola with (h,k)=(-1,-2),p=1