What is (y+2)^2=-10(x+6) ?

The solution to (y+2)^2=-10(x+6) is Parabola with (h,k)=(-6,-2),p=-5/2

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(y+2)^2=-10(x+6)

(y + 2)^{2} = - 10 (x + 6)

(h, k) = (- 6, - 2), p = - \frac{5}{2}

Solution steps

(y + 2)^{2} = - 10 (x + 6)

Rewrite

(y + 2)^{2} = - 10 (x + 6)

in the standard form:

4 (- \frac{5}{2}) (x - (- 6)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 6, - 2), p = - \frac{5}{2}

(x - 5)^{2} = - 27 (y - 1)

y = - 0.002 x^{2} + 0.51 x

x^{2} - 6 x + 3 y + 18 = 0

x + 9 = y^{2} - 3

- x^{2} - 4 x + y + 12 > 0

What is (y+2)^2=-10(x+6) ?
The solution to (y+2)^2=-10(x+6) is Parabola with (h,k)=(-6,-2),p=-5/2