What is 4^2+4y^2+16x-8y-5=0 ?

The solution to 4^2+4y^2+16x-8y-5=0 is Parabola with (h,k)=(-7/16 ,1),p=-1

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4^2+4y^2+16x-8y-5=0

4^{2} + 4 y^{2} + 16 x - 8 y - 5 = 0

(h, k) = (- \frac{7}{16}, 1), p = - 1

Solution steps

4^{2} + 4 y^{2} + 16 x - 8 y - 5 = 0

Rewrite

4^{2} + 4 y^{2} + 16 x - 8 y - 5 = 0

in the standard form

4 (- 1) (x - (- \frac{7}{16})) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{16}, 1), p = - 1

x^{2} = 9 y - 81

(x - 1)^{2} = 2 (y - 1)

(x + 1)^{2} = - 8 (y + 4)

(x - 3)^{2} = 12 (y + 2)

3 y^{2} + 6 y - 4 x + 15 = 0

What is 4^2+4y^2+16x-8y-5=0 ?
The solution to 4^2+4y^2+16x-8y-5=0 is Parabola with (h,k)=(-7/16 ,1),p=-1