What is 2y^2-2x-2y+9=0 ?

The solution to 2y^2-2x-2y+9=0 is Parabola with (h,k)=(17/4 , 1/2),p= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2y^2-2x-2y+9=0

2 y^{2} - 2 x - 2 y + 9 = 0

(h, k) = (\frac{17}{4}, \frac{1}{2}), p = \frac{1}{4}

Solution steps

2 y^{2} - 2 x - 2 y + 9 = 0

Rewrite

2 y^{2} - 2 x - 2 y + 9 = 0

in the standard form

4 \cdot \frac{1}{4} (x - \frac{17}{4}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{17}{4}, \frac{1}{2}), p = \frac{1}{4}

\frac{( z ^{2} + 2 \cdot z + I )}{( 1 - z )} = - 1

(y + 4)^{2} = 4 (x + 1)

(x + 1)^{2} = - 8 (y - 4)

x = - 7 y^{2}

(y + 1)^{2} + 2 x = 4

What is 2y^2-2x-2y+9=0 ?
The solution to 2y^2-2x-2y+9=0 is Parabola with (h,k)=(17/4 , 1/2),p= 1/4