en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2=12y

Solution

foci

x^{2} = 12 y

Solution

(0, 3)

Solution steps

Rewrite

x^{2} = 12 y

in the standard form:

4 \cdot 3 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 3

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 3)

Refine

(0, 3)

Popular Examples

vertices f(x)=x^2+4x+5 vertices

f (x) = x^{2} + 4 x + 5

4 x^{2} + y^{2} = 4

y^{2} = 4 a x

x^{2} - y^{2} = 15

x^{2} + y^{2} = 16

Frequently Asked Questions (FAQ)

What is the foci x^2=12y ?
The foci x^2=12y is (0,3)