What is -2x^2-20x+y-46=0 ?

The solution to -2x^2-20x+y-46=0 is Parabola with (h,k)=(-5,-4),p= 1/8

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-2x^2-20x+y-46=0

- 2 x^{2} - 20 x + y - 46 = 0

(h, k) = (- 5, - 4), p = \frac{1}{8}

Solution steps

- 2 x^{2} - 20 x + y - 46 = 0

Rewrite

- 2 x^{2} - 20 x + y - 46 = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- 4)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 4), p = \frac{1}{8}

(y + 3)^{2} = \frac{1}{2} (x + 16)

x^{2} = 20 + y

(X - 3)^{2} = - 4 (y - 1)

2 + y^{2} + 8 x - 14 y + 1 = 0

x = 4 + 6 y - 2 y^{2}

What is -2x^2-20x+y-46=0 ?
The solution to -2x^2-20x+y-46=0 is Parabola with (h,k)=(-5,-4),p= 1/8