What is x^2-4y-2x-40y-103=0 ?

The solution to x^2-4y-2x-40y-103=0 is Parabola with (h,k)=(1,-26/11),p=11

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x^2-4y-2x-40y-103=0

x^{2} - 4 y - 2 x - 40 y - 103 = 0

(h, k) = (1, - \frac{26}{11}), p = 11

Solution steps

x^{2} - 4 y - 2 x - 40 y - 103 = 0

Rewrite

x^{2} - 4 y - 2 x - 40 y - 103 = 0

in the standard form

4 \cdot 11 (y - (- \frac{26}{11})) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - \frac{26}{11}), p = 11

(x - 2)^{2} = - 32 (y - 5)

x^{2} + y - 3 = 0

(17 + x) = 34 x_{-} r (x)

x = 2 (y + 1)^{2} - 2

y > (x - 5) (x + 1)

What is x^2-4y-2x-40y-103=0 ?
The solution to x^2-4y-2x-40y-103=0 is Parabola with (h,k)=(1,-26/11),p=11