What is ((x+2)^2}{25}+\frac{(y-1)2)/9 =1 ?

The solution to ((x+2)^2}{25}+\frac{(y-1)2)/9 =1 is Parabola with (h,k)=(-2, 11/2),p=-25/18

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((x+2)^2}{25}+\frac{(y-1)2)/9 =1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) 2}{9} = 1

(h, k) = (- 2, \frac{11}{2}), p = - \frac{25}{18}

Solution steps

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) \cdot 2}{9} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) \cdot 2}{9} = 1

in the standard form:

4 (- \frac{25}{18}) (y - \frac{11}{2}) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{11}{2}), p = - \frac{25}{18}

\frac{w + v ^{2}}{5} = 12

x^{2} - 4 x - 25 y - 96 = 0

y^{2} = x + 6

y^{2} = x + 7

y^{2} = x + 8

What is ((x+2)^2}{25}+\frac{(y-1)2)/9 =1 ?
The solution to ((x+2)^2}{25}+\frac{(y-1)2)/9 =1 is Parabola with (h,k)=(-2, 11/2),p=-25/18