What is 2f(x)=x^2-5x+4 ?

The solution to 2f(x)=x^2-5x+4 is Parabola with (h,k)=(5/2 ,-9/8),p= 1/2

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2f(x)=x^2-5x+4

2 f (x) = x^{2} - 5 x + 4

(h, k) = (\frac{5}{2}, - \frac{9}{8}), p = \frac{1}{2}

Solution steps

2 y = x^{2} - 5 x + 4

Rewrite

2 y = x^{2} - 5 x + 4

in the standard form

4 \cdot \frac{1}{2} (y - (- \frac{9}{8})) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - \frac{9}{8}), p = \frac{1}{2}

3 (4 + y^{2}) = 5 z

y^{2} + 8 x + 2 y - 15 = 0

y^{2} + 4 x + 6 y + 17 = 0

y \geq x^{2} + 2 x + 1

(y - 1)^{2} = 16 (x - 1)

What is 2f(x)=x^2-5x+4 ?
The solution to 2f(x)=x^2-5x+4 is Parabola with (h,k)=(5/2 ,-9/8),p= 1/2