What is the foci (y^2}{16}-\frac{x^2)/9 =1 ?

The foci (y^2}{16}-\frac{x^2)/9 =1 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2}{16}-\frac{x^2)/9 =1

foci

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 3^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

x^{2} + y^{2} + 4 y = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} + y^{2} = 2

x^{2} + y^{2} - 6 x - 8 y = 0

What is the foci (y^2}{16}-\frac{x^2)/9 =1 ?
The foci (y^2}{16}-\frac{x^2)/9 =1 is (0,5),(0,-5)