What is (y-4)^2=-4(x-4) ?

The solution to (y-4)^2=-4(x-4) is Parabola with (h,k)=(4,4),p=-1

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(y-4)^2=-4(x-4)

(y - 4)^{2} = - 4 (x - 4)

(h, k) = (4, 4), p = - 1

Solution steps

(y - 4)^{2} = - 4 (x - 4)

Rewrite

(y - 4)^{2} = - 4 (x - 4)

in the standard form:

4 (- 1) (x - 4) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 4), p = - 1

\frac{1}{3} y^{2} - \frac{5}{6} y + 2 x + \frac{1}{6} = 0

x^{2} - 16 y = 0

4 x^{2} + 48 y + 12 x - 159 = 0

y - 3 x^{2} + 10 x = 5

x, 2 x^{2} + 5 x + 2 = - 3 (2 w + 1)

What is (y-4)^2=-4(x-4) ?
The solution to (y-4)^2=-4(x-4) is Parabola with (h,k)=(4,4),p=-1