What is 5y^2+2x-21y+20=0 ?

The solution to 5y^2+2x-21y+20=0 is Parabola with (h,k)=(41/40 , 21/10),p=-1/10

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5y^2+2x-21y+20=0

5 y^{2} + 2 x - 21 y + 20 = 0

(h, k) = (\frac{41}{40}, \frac{21}{10}), p = - \frac{1}{10}

Solution steps

5 y^{2} + 2 x - 21 y + 20 = 0

Rewrite

5 y^{2} + 2 x - 21 y + 20 = 0

in the standard form

4 (- \frac{1}{10}) (x - \frac{41}{40}) = (y - \frac{21}{10})^{2}

Therefore parabola properties are:

(h, k) = (\frac{41}{40}, \frac{21}{10}), p = - \frac{1}{10}

(y - 3)^{2} = - \frac{1}{2} (x + 3)

x = 3 y^{2} - 6 y + 5

Y - X^{2} = 2

0 = - 39 - 3 y - 4 x^{2} + 32 x

(3 x - 6) (x + 1) < o

What is 5y^2+2x-21y+20=0 ?
The solution to 5y^2+2x-21y+20=0 is Parabola with (h,k)=(41/40 , 21/10),p=-1/10